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Hans Nieuwenhuis
05-Sep-2008, 12:17 AM
Hi,

I read in your FAQ that the file size of an executable compiled with EurekaLog will rise with about 0.5%.

My executable compiled without EurekaLog is 108 Kbyte.
My executable compiled with EurekaLog is 124 Kbyte.

That's an increase of 16 KByte = 16 / 108 * 100 = 14.8%

I don't mind 16 Kbyte added, but I don't know how much will be added if my program is, say 1 MByte in size. Will it also be 16 KByte? Or 14.8%?

I'm using EurekaLog 6.0.16 RC 6

admin
08-Sep-2008, 05:02 PM
Hi Hans,

I have just updated the FAQ page.

See it here:
http://www.eurekalog.com/faq_dotnet.php

The answer is:
EurekaLog increases the compiled file size by about 16KBytes (and add a new EurekaLog.dll file of about 1Mb).

PS: the new FAQ page is related to the upcoming new 6.0.16 release.